Find the missing x- and y-values and Pythagorean triples using the identity given
​A Pythagorean triple consists of three positive integers a, b, and c, that satisfy the equation from the Pythagorean theorem, thus, a² + b² = c², such triple is commonly written (a,b,c).
​We are given the equation : (x²-y²)² + (2xy)² = (x²+y²)² since this, we have :
​a = (x²-y²)
b = (2xy)​
c = (x²+y²)​
​Question 1)
​X Value: 4
Y Value: 3​
Pythagorean triples: ?​
Now we can replace the values of x and y, to determine a, b and c.​
a = (x²-y²) = (4²-3²) = 16-9 = 7​
​b = (2xy) = (2*4*3) = 24
​c = (x²+y²) = (4²+3²) = 16+9 = 25
​Answer 1 : Pythagorean triples : (7,24,25)
Question 2)​
X Value: 5​
​Y Value: ?
Pythagorean Triples: (9,40,41)​
​Now we have a, b, and c, to determine Y
​b = (2xy) = 40
Y = 40/2x = 40/2*5 = 40/10 = 4​
​Answer 2 : Y = 4
Question 3)​
X Value: ?​
Y Value: 3​
​Pythagorean Triples: (27,36,45)
Now we have a, b, and c, to determine X​
​b = (2xy) = 36
X = 36/2y = 36/2*3 = 36/6 = 6​
Answer 3 : X = 6​
Question 4) ​
X Value: 7​
​Y Value: 5
Pythagorean Triples: ?​
​Now we can replace the values of x and y, to determine a, b and c.
​a = (x²-y²) = (7²-5²) = 49-25 = 24
b = (2xy) = (2*7*5) = 70​
c = (x²+y²) = (7²+5²) = 49+25 = 74​
​Answer 4 : Pythagorean triples : (24,70,74)
Hope this helps!​​​​​
​​[tex]\textit{\textbf{Spymore}}[/tex]​​​​​​
