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An ordinary fair die is a cube with the numbers 1 through 6 on the sides. Imagine that such a die is rolled twice in succession and that the faces of the 2 rolls are added together. This sum is recorded of single trial of a random experiment. Event A: The sum is greater than 6 Event B the sum is divisible by 6

Respuesta :

Answer:

A. 5/9 Β  Β B. 1/6.

Step-by-step explanation:

Total possible events = 6*6 = 36.

A. Β The possible combinations for the sum Β being <= 6 are:

1 ,1 Β 2,2 Β  3,3 Β  1,2 Β 1,3 Β 1,4 Β 1,5 Β 2,1 Β  2,3 Β 2,4 Β 3,1 Β  3,2 Β 3,3 Β 4,1 Β 4,2 Β 5,1

= 16

So Probability of Sum > 6 = Β (36-16) / 36

= 20/36

= 5/9.

B. Β  Possible combinations where the sum is divisible by 6 Β are

3,3 Β 2,4 Β 4,2 Β 1,5 Β 5,1. 6,6 Β  = Β  6.

So the required probability = Β 6/36

= 1/6.

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