Answer:
[tex]5.00x10^{3} Â Kg[/tex]
Explanation:
There are two reactions taking place and the product of the first is a reactant at the other, so writing down the balanced chemical equations is the first step in determinimg the proportions
1)                    C + O2 → CO2
1. Molar mass       C = 12.0107 g/mol       Â
2. Number of moles  [tex]1.00x10^{3}  Kg[/tex] of carbon has [tex]8.33x10^{4}  mol[/tex] of C
Remember: mol(n)
[tex]n=\frac{sample mass}{molar mass}[/tex]
Â
2)                   CO2 + 2NH3 → CO(NH3)2 + H2O
1. Molar mass       CO(NH3)2 = 60.02 g/mol   Â
2. Proportions        the urea syntheres has a proportion of 1:1 with carbon dioxyde, so there is [tex]8.33x10^{4}  mol[/tex] of CO(NH3)2
[tex]8.33x10^{4} Â mol[/tex] of CO(NH3)2 has [tex]5.00x10^{3} Â Kg[/tex]
[tex]Sample mass = n*molar mass[/tex]