The larger of two numbers exceeds twice the smaller by one. The system of equations are y = 2x + 1 and y + 6 = 3x. So option 2 is correct
Solution:
Given, y is the larger number and x be the smaller number.
We have to find which of the given systems of equations represents the word problem? Â
Now, the larger of two numbers exceeds twice the smaller by one. Â
Then, y – (2 × x) = 1 ⇒ y – 2x = 1 ⇒ y = 2x + 1
And, three times the smaller exceeds the larger by six Â
Then, 3 × x – y = 6 ⇒ 3x – y = 6 ⇒ y + 6 = 3x
Hence, the system of equations are y = 2x + 1 and y + 6 = 3x. so option 2 is correct.