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Given the following cross between parents of the genotypes AABBCc × AabbCc, assume simple dominance for each trait and independent assortment. What proportion of the progeny will be expected to phenotypically resemble the first parent?

Respuesta :

Answer:

3/4

Explanation:

The first parent with the "AABBCc" genotype would express the dominant trait for all the three loci since the mentioned loci exhibit simple dominance for each trait and independent assortment. Therefore, the desired progeny should also exhibit the dominant trait for all three loci.  

Parents= AABBCc × AabbCc  

AA x Aa= 1/2 AA (dominant): 1/2 Aa (dominant) = 100% dominant progeny  

BB x bb = Bb (dominant) = 100% dominant progeny  

Cc x Cc = 1/4 CC (dominant): 1/2 Cc (dominant): 1/4 cc (recessive) = 3/4 dominant : 1/4 recessive progeny  

Therefore, the proportion of the progeny showing the dominant trait for all the three loci= 1 x 1 x 3/4 = 3/4

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