Answer:
(c) Total Number of moles = 3
Explanation:
To solve this question we have to follow the stoichiometry of the reaction and the fact that at equilibrium we have 1 mol of CH₃OH using the mnemonic helper RICE ( Reaction, Initial, Change, Equilibrium) as follows:
R       CO(g) + 2 H₂ (g)  ⇄  CH₃OH (g)
I (mol) Â Â Â Â 2 Â Â Â Â Â Â 3 Â Â Â Â Â Â Â Â Â Â 0
C (mol)    -x     x -2x        + x
E (mol)    2-x     3-2x          x
But we are told that at equilibrium x = mol CH₃OH = 1 , then at equilibrium we will have
E (mol) Â Â Â 2-(1) Â Â Â 3-2(1) Â Â Â Â Â Â 1
E (mol) Â Â Â Â Â 1 Â Â Â Â Â Â 1 Â Â Â Â Â Â Â Â 1
Therefore, the total number of moles of gas present in the container at equilibrium was 3