Respuesta :
Answer:
a) Â Em = 332.8 J , b) # jump = 13, c) Â It is reasonable since there are not too many jumps , d) lower the calories consumed
Explanation:
a) Let's use energy conservation
Initial. On the floor
       Em₀ = K = ½ m v²
Final. The highest point
       Emf = U = m g h
Energy is conserved
       Em₀ = Emf
       ½ m v² = m g h
       h = ½ v² / g
      h = ½ 3.2² /9.8
      h = 0.52 m
b) When he was at home he maintained his weight with 2500 cal / day. In his parents' house he consumes 3500 cal / day, the excess of calories is
      Q = 3500 -2500 = 1000cal / day
Let's reduce this value to the SI system
       Q = 1000 cal (4,184 J / 1 cal) = 4186 J / day
Now the energy in each jump is
        Em = K = ½ m v²
        Em = ½ 65 3.2²
        Em = 332.8 J
They indicate that the body can only use 25% of this energy
       Em effec = 0.25 332.8 J
       Em effec = 83.2 J
This is the energy that burns the body
Let's use a Proportion Rule (rule of three), if a jump spends 83.2J how much jump it needs to spend 1046 J
       # jump = 1046 J (1 jump / 83.2 J)
       # jump = 12.6 jumps / day
       # jump = 13 Â
c) It is reasonable since there are not too many jumps
d) That some days consume more vegetables to lower the calories consumed
