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Variations in the resistivity of blood can give valuable clues about changes in various properties of the blood. Suppose a medical device attaches two electrodes into a 1.8-mm-diameter vein at positions 4.8cm apart.What is the blood resistivity if a 9.0 V potential difference causes a 280?A current through the blood in the vein?

Respuesta :

Answer:

ρ = 1.70 Ωm

Explanation:

given data

diameter = 1.8 mm

distance = 4.8 cm

volt = 9 V

potential difference = 280

solution

we know that Resistance that is express as

Resistance =  [tex]\frac{V}{I}[/tex]   ..............1

V = I × R

and

V = I  × [tex]\frac{\rho L}{A}[/tex]    ..........2

put here value we get

9 = 280 ×[tex]10^{-6}[/tex] × [tex]\frac{\rho \times 0.048}{\pi \times 0.9^2 \times 10^{-6} }[/tex]  

ρ = 1.70 Ωm

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