Answer:
Explanation:
1)
Given data:
Number of moles of aluminium = 0.223 mol
Mass of silver produced = ?
Solution:
Chemical equation:
3AgNO₃  +  Al  →  3Ag + Al(NO₃)₃
Now we will compare the moles of Al with silver.
                Al      :       Ag
                1       :       3
                0.223  :     3×0.223= 0.669 mol
Grams of silver:
Mass = number of moles × molar mass
Mass = 0.669 mol × 107.87 g/mol
Mass = 72.2 g
2)
Given data:
Number of moles of mercury(II) oxide produced = 3.12 mol
Mass of mercury = ?
Solution:
Chemical equation:
2Hg + O₂  →  2HgO
Now we will compare the moles of mercury with mercury(II) oxide.
             HgO     :     Hg
              2       :      2
             3.12      :    3.12
Mass of Hg:
Mass = number of moles × molar mass
Mass = 3.12 mol × 200.59 g/mol
Mass = 625.84 g
3)
Given data:
Number of moles of dinitrogen pentoxide = 12.99 mol
Mass of oxygen = ?
Solution:
Chemical equation:
2N₂  + 5O₂  →  2N₂O₅
Now we will compare the moles of Nâ‚‚Oâ‚… with oxygen.
         N₂O₅      :      O₂
           2       :       5
          12.99    :     5/2×12.99 = 32.48 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 32.48 mol × 32 g/mol
Mass = 1039.36 g
4)
Given data:
Number of moles of benzene = 0.103 mol
Mass of carbon dioxide = ?
Solution:
Chemical equation:
2C₆H₆  + 15O₂  →  12CO₂ + 6H₂O
Now we will compare the moles of Nâ‚‚Oâ‚… with oxygen.
         C₆H₆     :      CO₂
           2       :       12
          0.103    :     12/2×0.103 = 0.618 mol
Mass of carbon dioxide:
Mass = number of moles × molar mass
Mass = 0.618 mol × 44 g/mol
Mass = 27.192 g
