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A truck runs into a pile of sand, moving 0.80 m as it slows to a stop. The magnitude of the work that the sand does on the truck is 5.5×105J. Part A Determine the magnitude of the average force that the sand exerts on the truck

Respuesta :

ajeigbeibraheem

Answer:

687,500 N

Explanation:

Workdone = Force × Distance

Making force the subject of the formula; we have:

Force =[tex]\frac{workdone}{distance}[/tex]

Given that:

workdone  = 5.5×10⁔ J

Distance = 0.80 m

∎ Force = [tex]\frac{5.5*10^5}{0.8}[/tex]

Force = 687,500 N

asuwafohjames

Answer:

6.875×10⁔  N.

Explanation:

Force: This can be defined as the product of mass and acceleration or it can be defined as the ratio of work done and distance. The S.I unit of force is Newton.

W = F×d................. Equation 1

Where W = work done, F = force, d = distance.

make F the subject of the equation

F = W/d.................... Equation 2

Given: W = 5.5×10⁔ J, d = 0.8 m

Substitute into equation 2

F =  5.5×10⁔ /0.8

F = 6.875×10⁔  N.

Hence the force exerted on the truck by the sand = 6.875×10⁔  N.

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