Answer:
d. 0.222 g​
Explanation:
Given parameters:
volume of water  = 71.9mL  = 0.0719L
pressure  = 1053.8kPa = 10.4atm
temperature  = 738K
Unknown:
mass of water  = ?
Solution:
To find the mass of water, we need to obtain the number of moles from the given parameters.
This can be done using the ideal gas law;
       PV  = nRT
where P is the pressure
     V is the volume
      n is the number of moles
      R is the gas constant
      T is the temperature
   Input the parameters to find n;
     10.4 x 0.0719  = n x 0.082 x 738
         n  = 0.012moles
Mass of water vapor  = number of moles x molar mass
     molar mass of H₂O  = 2 + 16  = 18g/mol
Mass of water vapor  = 0.012 x 18 = 0.22g
