Answer:
[tex]\large \boxed{1.85:1}[/tex]
Explanation:
The density of a substance is directly proportional to the molar mass and the number of atoms per unit cell, and inversely proportional to the volume of the unit cell.
The BCC unit cell of CsCl contains one Kâș and one Clâ» ion, while the SC unit cell contains four Naâș and four Clâ» ions.
[tex]\dfrac{\text{CsCl density}}{\text{NaCl density}} = \dfrac{\text{Atoms of Cs}}{\text{Atoms of Ca}} \times \dfrac{\text{MM of CsCl}}{\text{MM of NaCl}} \times \dfrac{\text{Vol. of NaCl unit cell}}{\text{Vol. of CsCl unit cell}}\\\\= \dfrac{1}{4} \times \dfrac{\text{2.88}}{\text{1}} \times \dfrac{1.37^{3}}{1^{3}} = \dfrac{1.85}{1}\\\\\text{The ratio of the density of CsCl to that of NaCl is $\large \boxed{\mathbf{1.85:1}}$}[/tex]