Answer:
 3.527 seconds
Explanation:
The height of the falling water, assuming no friction or air resistance, is given by ...
 h(t) = -(1/2)gt² +61
where g is the standard gravity value, 9.80665 m/s².
The the time required for h(t) = 0 is ...
 1/2gt² = 61
 t² = 2·61/g
 t = √(2·61/9.80665) ≈ 3.527 . . . . seconds