Respuesta :
Answer:
[tex]t=\frac{219.2-205}{\frac{18}{\sqrt{20}}}=3.528[/tex] Â Â
[tex]p_v =2*P(t_{19}>3.528)=0.0022[/tex] Â Â
If we compare the p value and a significance level for example [tex]\alpha=0.05[/tex] we see that [tex]p_v <\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the lifetime is signficantly different from 205 hours. Â Â
Step-by-step explanation:
Data given and notation  Â
[tex]\bar X=219.2[/tex] represent the sample mean
[tex]s=18[/tex] represent the sample standard deviation  Â
[tex]n=20[/tex] sample size  Â
[tex]\mu_o =205[/tex] represent the value that we want to test  Â
[tex]\alpha[/tex] represent the significance level for the hypothesis test. Â Â
t would represent the statistic (variable of interest) Â Â
[tex]p_v[/tex] represent the p value for the test (variable of interest) Â Â
State the null and alternative hypotheses. Â Â
We need to apply a two tailed  test. Â
What are H0 and Ha for this study? Â Â
Null hypothesis: Â [tex]\mu = 205[/tex] Â
Alternative hypothesis :[tex]\mu \neq 205[/tex] Â
Compute the test statistic Â
The statistic for this case is given by: Â
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1) Â Â
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value". Â Â
Calculate the statistic  Â
We can replace in formula (1) the info given like this: Â Â
[tex]t=\frac{219.2-205}{\frac{18}{\sqrt{20}}}=3.528[/tex] Â Â
Give the appropriate conclusion for the test Â
The degreed of freedom are:
[tex] df = n-1= 19[/tex]
Since is a two sided test the p value would be: Â Â
[tex]p_v =2*P(t_{19}>3.528)=0.0022[/tex] Â Â
Conclusion  Â
If we compare the p value and a significance level for example [tex]\alpha=0.05[/tex] we see that [tex]p_v <\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the lifetime is signficantly different from 205 hours. Â Â
Answer:
H0: mu equals 205 vs. H1: mu not equals 205.
Step-by-step explanation:
A null hypothesis (H0) is a statement from a population parameter which is either rejected or accepted (fail to reject) upon testing. It expresses equality.
An alternate hypothesis (H1) is also a statement from the population parameter which negates the null hypothesis and is accepted if the null hypothesis is true. It expresses inequality.
A two-tailed test is one in which the alternate hypothesis is expressed using any of the inequality signs below:
not equal to, less than or equal to, greater than or equal to.