Answer:
111249.41m/s²
Explanation:
Mass of the wire m = 40g = 0.04 Kg
Length of the wire l = 7 m
Linear density of wire μ = m/l
= 0.04/7
= 0.0057 Kg/m
Frequency n = 630 Hz
Wavelength Ī» = 0.5 m
Amplitude A = Ā 7.1mm = 0.0071m
Speed of the wave v = nĪ»
= 630*0.5
= 315 m/s
Angular speed Ļ = 2Ļn
= 2Ļ*630
= 3958.40 rad/s
Maximum transeverse acceleration
a = Ļ^2 A
= 3958.40² à 0.0071m
= 111249.41m/s²