Answer:
Total no  of different ways can the 4 computers be chosen  = 70
Step-by-step explanation:
Given -
A computer retail store has 8 personal computers in stock.A buyer wants to purchase 4 of them.
(Using the combination formula)
The combination of n events taking r at a time = [tex]\mathbf{\binom{n}{r}}[/tex]
where n = 8 and r = 4
Total no  of different ways can the 4 computers be chosen = [tex]\mathbf{\binom{8}{4}}[/tex]
  =  [tex]\boldsymbol{\frac{8!}{(4!)(4!)}}[/tex]
= Â 70
