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A Carnot refrigeration cycle is executed in a closed system in the saturated liquid-vapor region using 3.2 kg of R-134a. The maximum absolute temperature in the cycle is 1.1 times the minimum absolute temperature, and the net work into the cycle is 27 kJ. a. (6) Draw this cycle on p-v coordinates, labeling the isentropic compression as process 1-2. Indicate where Qin and Qout are located. b7) Calculate what Quote is, in kJ

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mudamoon97

Answer:

Explanation:

Given Data

Mass of refrigerant,  m  = 3.2kg

Work input to the cycle, Wnet = 27kj

The expression for coefficient of performance

C O P  r = Q L /˙ W n e t ............(A)

The expression for maximum performance of refrigerator,

C OP r = T L /T H  − T L  . . . . . . . . . ( B )

Here,  T L

is cold temperature reservoir,  T H  is hot temperature reservoir.

Since,  T H = 2 T L . . . . . ( C )

Comparing equation (A) and (B),

Q L /˙ W n e t  = T L /T H − T L

Substituting all the respective value in above equation,

Ë™

Q L /27  = T L /1.1T L − T L

Q L = 270kj

The expression for heat rejected,

Q H = W n e t  +  Q L

Q H=27 + 270

QH = 340kj

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