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2. A circuit consists of a 10.0-ohm resistor,
a 15.0-ohm resistor, and a 20.0-ohm
resistor connected in parallel across a
9.00-volt battery. What is the equivalent
resistance of this circuit?
(1) 0.200 12 (3) 4.62 1
(2) 1.95.22
(4) 45.012

Respuesta :

oladayoademosu

Answer:

(3) 4.62 ohms

Explanation:

Te equivalent resistance R is gotten from

1/R = 1/Rā‚ + 1/Rā‚‚ + 1/Rā‚ƒ where Rā‚ = 10.0 ohm, Rā‚‚ = 15.0 ohm and Rā‚ƒ = 20.0 ohm

1/R = 1/10 + 1/15 + 1/20

1/R = 0.1 + 0.0667 + 0.05

1/R = 0.2167

R = 1/0.2167

R = 4.62 ohms

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