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Let set C = {even numbers between 1 and 99} and set D = {numbers between 1 and 150 that are evenly divisible by 10}.

What is C ∩ D?

Respuesta :

[tex]C= [2,4,6,8,10.........98][/tex] 

[tex]D=[10,20,30,40,50,.....140][/tex]

C ∩ D = [tex][10,20,30,40,50,60,70,80,90,][/tex]
   
[tex][All \ even \ numbers \ between \ 1 \ and \ 99][/tex] 

[tex]Answer = [10, 20, 30, 40, 50, 60, 70, 80, 90][/tex]

C∩D = {10, 20, 30, 40, 50, 60, 70, 80, 90}

What is the intersection of two sets?

The intersection of two sets A and B is the set of all those elements which are common to both A and B.

According to the given question.

We have, two sets

C = { even numbers between 1 and 99}

⇒ C = { 2, 4, 6, 8, 10, 12, 14, 16, ........., 98}

And,

D = { numbers between 1 and 150 that are evenly divisible by 10}

⇒ D = { 10, 20, 30, 40, 50, 60, .......150}

Therefore, the intersection of set C and D is given by

C∩D

= { all the even numbers between 1 to 99 which are evenly divisible by 10}

= {10, 20, 30, 40, 50, 60, 70, 80, 90}

Hence, C∩D = {10, 20, 30, 40, 50, 60, 70, 80, 90}

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