Answer:
Tl³⺠+ Sn²⺠ā Tlāŗ + Snā“āŗ
Explanation:
In a redox reaction, one compound is oxidized (Loosing electrons) whereas the other compound is reduced (Gaining electrons). In the reaction, the half-reactions of oxidation and reduction are:
Sn²⺠ā 2eā» + Snā“āŗ (Oxidation: Loosing electrons)
Tl³⺠+ 2eā» ā Tlāŗ (Reduction: Gaining electrons)
The sum of both reactions gives:
Tl³⺠+ Sn²⺠+ 2eā» ā Tlāŗ + 2eā» + Snā“āŗ
Subtracting the electrons: