Complete Question
A student bikes to school by traveling first dN = 0.900 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south.
Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form.
Express your answer as two numbers separated by a comma. Be careful with your signs.
Answer:
The value is  [tex]dT  =  ( -0.3,  0.8)[/tex]
Explanation:
From the question we are told that
  The first displacement is  [tex]dN  =  0.900 \  due  \  North[/tex] i.e positive  y-axis
  The  second displacement is  [tex]dW =  0.300 \  miles  \  due \  west[/tex] i.e negative  x-axis
  The final displacement is  [tex]dS =  0.100 \  miles \ due \ south[/tex] i.e  negative  y-axis
Generally dW in component for is Â
   [tex]dW =  (-0.3 ,  0)[/tex] Â
Generally the  total displacement of the student is mathematically represented as
   [tex]dT  =  ( -0.3,  (0.90 - 0.10))[/tex]
   [tex]dT  =  ( -0.3,  0.8)[/tex]
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