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You are out on an early morning jog when you see a family of squirrels in a tree that lies directly in your path. A squirrel on a branch 20 m high in the tree drops an acorn directly above your head as you run with speed 1.5 m/s beneath the squirrel's position. How far behind you does the acorn hit the ground?

Respuesta :

Answer:

The acorn hit the ground 3 m far away from me.

Explanation:

Here ,

time taken by the  acorn to fall be 't',

Height of the tree is 20m ,

so [tex]S= 20m[/tex]

Acceleration due to gravity is -[tex]a=9.8\frac{m}{s^2}\approx 10 \frac{m}{s^2}[/tex]

Initial velocity is 0 ,so  u=0

According to the second equation of motion ,

[tex]s=ut+\frac{1}{2} at^2[/tex]

[tex]20=\frac{1}{2} \times10\times t^2[/tex]

[tex]t^2=4[/tex]    

[tex]t=2[/tex]sec.

Distance travelled by you in 2 sec

[tex]\text{Distance} = \text{Speed} \times \text{Time}[/tex]

Put speed=  1.5m/s² and time = 2sec

[tex]Distance= 1.5 \times 2\\Distance=3m[/tex]

 Hence , the acorn hit the ground 3m far away from me.            

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