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Two blocks are connected by a string over a pulley. The hanging block has a mass of 8-kg and the one on the plane has a mass of m2. If the coefficient of static friction is .8 what is the minimum mass that m2 must be in order for the objects to be in a state of static equilibrium.

Two blocks are connected by a string over a pulley The hanging block has a mass of 8kg and the one on the plane has a mass of m2 If the coefficient of static fr class=

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Gojumathew1

Answer:

Let f be force of friction on the blocks kept on inclined plane. T be tension in the string

For motion of block on the inclined plane in upward direction

T - mā‚gsin40 - f = mā‚a

f = Ī¼ mā‚gcos40

For motion of hanging Ā block on Ā in downward direction

mā‚‚g Ā - T = mā‚‚ a

Adding to cancel T

mā‚‚g - - mā‚gsin40 - Ā Ī¼ mā‚gcos40 = a ( mā‚+mā‚‚ )

a = Ā  g (mā‚‚ - - mā‚sin40 - Ā Ī¼ mā‚cos40) / ( mā‚+mā‚‚ )

Putting the values

a = 9.8 ( 4.75 - 2.12-1.045) / 7.6

2.04 m sā»Ā²

Mā‚‚ will go down and Mā‚ will go up with acceleration .

Explanation:

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