Answer:
the kinetic energy of body B is twice the kinetic energy of body A
Explanation:
The kinetic energy of a body is given by
     K = ½ m v²
If two objects leave the same point, suppose that at the same height when they reach the ground they have the same velocity.
Therefore if the mass of body b is twice the mass of body A
     [tex]m_{b} = 2 m_{a}[/tex]
     [tex]K_{b}[/tex] = ½ (2 [tex]m_{a}[/tex]) v²
     K_{b} = 2 (½ m_{a} v²)
     K_{b} = 2 K_{a}
therefore the kinetic energy of body B is twice the kinetic energy of body A