Answer:
11.8g of CaClâ‚‚ would be required
Explanation:
To solve this question we need to find the moles of AgNO₃ in the solution. Thus, and using the chemical reaction we can find the moles of CaCl₂ required for a complete reaction and its mass as follows:
Moles AgNO₃:
420mL = 0.420L * (0.506mol / L) = 0.213 moles AgNO₃
Moles CaClâ‚‚:
Based on the chemical reaction, 2 moles of AgNO₃ react per mole of CaCl₂.
The moles of CaClâ‚‚ that will react are:
0.213 moles AgNO₃ * (1mol CaCl₂ / 2 mol AgNO₃) = 0.106 moles CaCl₂
Mass CaClâ‚‚ -Molar mass: 110.98g/mol-
0.106 moles CaClâ‚‚ * (110.98g / mol) =
