Respuesta :
Answer:
math = Â 24
English = 16
Philosophy  = 8
Explanation:
Given that the college needs to make 8 less English courses available compared to math In each quarter
Let English  = x ,  math = x + 8   ( in each quarter )
philosophy demand by student in each quarter = 1/2*x = x/2
limit of all three courses in a classroom = 48
i.e. Â x + (x+ 8 ) + x/2 = 48
  = 2x + x/2 = 48 - 8
  = 2x + x/2 = 40 ∴  5x / 2 = 40
hence : x = 80 / 5 = 16
The number of sections of each course that the college should make available in each quarter to meet demand
math = x + 8 = 16 + 8 = 24
English = x  = 16
Philosophy = x/2 = 16 / 2 = 8