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Using the reaction of Zinc with dilute hydrochloric acid:
a) Write an ionic equation for the reaction, with state symbols. (3 marks)Β 
b) From your answer to part a construct two half equations to show electron transfer taking place.(2 marks)
c) Explain why this is a redox reactor (5 marks)Β 

Respuesta :

Answer:

a).

[tex]{ \rm{Zn {}^{2 + } _{(aq)}+ 2Cl {}^{ - } _{(aq)} β†’ ZnCl _{2(aq)} }} \\ [/tex]

b).

[tex]{ \rm{Zn {}^{2 + } _{(aq)} + 2e {}^{ - } β†’ Zn _{(aq)} }} \\ \\ { \rm{ Cl {}^{ - } _{(aq)} β†’ Cl _{(aq)} + {e}^{ - } }}[/tex]

[ e represents an electron ]

c).

It is a redox reaction because oxidation [ electron loss ] and reduction [ electron gain ] both take place in the overall reaction.

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