John rented a truck for one day there was a base fee of $20.95 and there was an additional charge of $.72 for each mile driven John had to pay $137.59 when he returned the truck for how many miles did he drive the truck

lets say miles = x 20.95 + .72x = 137. 59 = step 1 ) eliminate base fee both sides through opposite subtraction = 20.95 - 20.95 + .72x = 137. 59 -20.95 = .72x = 137. 59 -20.95 = .72x = 116.64 = step 2) eliminate cost per mile through division to both sides to find full mileage = 116. 64/ .72 = 162 miles and x = 162 as proved in reverse 162 * .72 = 116 64 charges of total found earlier therefore John had drove 162 miles is what you need to say.

John rented a truck for one day there was a base fee of $20.95 and there was an additional charge of $.72 for each mile driven John had to pay $137.59 when he returned the truck for how many miles did he drive the truck￼

Respuesta :

Otras preguntas

John rented a truck for one day there was a base fee of $20.95 and there was an additional charge of $.72 for each mile driven John had to pay $137.59 when he returned the truck for how many miles did he drive the truck