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A jar contains five black balls and seven white balls. two balls are drawn sequentially, but the first ball is replaced before the second drawn. the probability of drawing two white balls, given that at least one of the balls is white, is 7/17.

Respuesta :

The probability both balls are black, given that the first one is black, is gotten as;  ⁡/₁₂

What is the probability of Selection?

By using the probability of an event formula,

There are 5 black balls out of a total of 12 balls, so the probability of obtaining a black on a single draw is ⁡/₁₂, and the probability of obtaining a white is ⁷/₁₂

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Since the balls are drawn with replacement, the two draws are independent events.

Use Multiplication and Union Rules to obtain the following probability:

P(F) = P(B, B) + P(B, W)

P(F) = (⁡/₁₂ * ⁡/₁₂) + (⁡/₁₂ * ⁷/₁₂)

P(F) =  ⁡/₁₂

Thus, the probability both balls are black, given that the first one is black, is  ⁡/₁₂

Read more about probability of event at; https://brainly.com/question/7965468

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