Given the model from the question,
- The products are: Nâ‚‚, Hâ‚‚O and Hâ‚‚
- The reactants are: Hâ‚‚ and NO
- The limiting reactant is Hâ‚‚
- The balanced equation is: 3H₂ + 2NO —> N₂ + 2H₂O + H₂
Balanced equation
From the model given, we obtained the ffolowing
- Red => Oxygen
- Blue => Nitrogen
- White => Hydrogen
Thus, we can write the balanced equation as follow:
3H₂ + 2NO —> N₂ + 2H₂O + H₂
From the balanced equation above,
- Reactants: Hâ‚‚ and NO
- Product: Nâ‚‚, Hâ‚‚O and Hâ‚‚
How to determine the limiting reactant
3H₂ + 2NO —> N₂ + 2H₂O + H₂
From the balanced equation above,
3 moles of Hâ‚‚ reacted with 2 moles of NO.
Therefore,
5 moles of H₂ will react with = (5 × 2) / 3 = 3.33 moles of NO
From the calculation made above, we can see that only 3.33 moles of NO out of 4 moles given are required to react completely with 5 moles of Hâ‚‚.
Thus, Hâ‚‚ is the limiting reactant
Learn more about stoichiometry:
https://brainly.com/question/14735801
#SPJ1