The  profit function is R(x) = -0.5 (x - 50²) + 1150
- The domain of P(x)  is:  0 ≤ x ≤ 150
- Profit when producing 50 items = 1150
- Profit when producing 60 items = Â 1100
What is the profit function about?
Note that:
1. Profit  = Revenue - cost
P (x) =  0.5 ( x - 90²) + 4050 - 40x - 100 Â
= 0.5 ( x² - 180 + 8100 + 4050 - 40x - 100 Â
=0.5 x² - 50x - 100 Â
=0.5( x² - 100x) - 100 Â
=  -0.5 (x - 50²) + 1150
2. Â Since the minimum unit is 50.
Then  x ≤ 150
X = describe the item so it need to be a negative number
Hence the domain of P(x)  is:  0 ≤ x ≤ 150
3. Assume x = 50 , 60
R(50) = 1150 , R (60 ) = -0.5 (60-50)² + 1150 = 1100
4. R (x) = -0.5 (x-50)² + 1150  then 50 more unit is removed hence, Profit when producing 60 items =  1100
Therefore, The  profit function is R(x) = -0.5 (x - 50²) + 1150
- The domain of P(x)  is:  0 ≤ x ≤ 150
- Profit when producing 50 items = 1150
- Profit when producing 60 items = Â 1100
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