Ammonia is formed by a reaction between hydrogen and nitrogen as shown by the equation below. N2(g) + 3H2(g) = 2NH3(g) 1 mole of ammonia contains 17 g Therefore 10.78 g of ammonia are equivalent to 10.78/17 = 0.6341 moles The mole ratio of hydrogen to ammonia is 3 : 2 Therefore, moles of hydrogen used will be 0.6341 × 3/2 = 0.9512 moles 1 mole of hydrogen is equivalent to 2 g Thus, the mas of hydrogen will be 0.9512 moles × 2 = 1.9023 g
